Update- Go over previous day's Checkpoints
Bell Ringer0 1 -1 does not exist none of the above Solve the following algebraically: -½ ½ 0 does not exist none of the above ⅕ -⅕ 0 does not exist none of the above 3 -3 0 does not exist - none of these
ReviewLesson- Math Overview (so far)
- Numbers
- Relationships
- Shapes
- Change
- Limits (algebraically)
Exit Ticket- Posted on the board at the end of the block.
| Lesson Objectives
- How are limits found algebraically?
Standard(s)- APC.2
- Define and apply the properties of limits of functions.
- Limits will be evaluated graphically and algebraically.
- Includes:
- limits of a constant
- limits of a sum, product, and quotient
- one-sided limits
- limits at infinity, infinite limits, and non-existent limits*
- APC.3
- Use limits to define continuity and determine where a function is continuous or discontinuous.
- Includes:
- continuity in terms of limits
- continuity at a point and over a closed interval
- application of the Intermediate Value Theorem and the Extreme Value Theorem
- geometric understanding and interpretation of continuity and discontinuity
Past Checkpoints |