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 PostAssessment Reflection
 Differentiation Test 2 on this Friday, 10.03.14!
 Summative Exam 1 on next Friday, 10.10.14!
Calculate dy/dx for the following: y = x dy/dx = x dy/dx = y dy/dx = 1 dy/dx = 0 none of the above
2y = x dy/dx = x/2 dy/dx = 2y dy/dx = 2 dy/dx = 0 none of the above
xy = 1 dy/dx = x2 dy/dx = 1/x2 dy/dx = 1/x2 dy/dx = 2/x2 none of the above
x2y = x + 1 dy/dx = (x  2)/x3 dy/dx = (x  2)/x3 dy/dx = (x  2)/x2 dy/dx = (x  2)/x2 none of the above
y3 + y2  5y  x2 = 4 dy/dx = (2x) / (3y2 + 2y  5) dy/dx = (2x) / (3y2 + 2y + 5) dy/dx = (2x) / (3y2 + 2y  5) dy/dx = 2 / (3y2 + 2y  5)  none of the above
Review
 Secant vs. Tangent Line
 Definition of Derivative
 Importance of Derivative
 What does it allow us to do?
 Drawing a Tangent Line on a Graph
 Basic Differentiation Rules
 Constant Rule
 Power Rule
 Sum and Difference Rule
 Sine and Cosine Derivatives
 Derivative Notation
 Differentiation
 Rates of Change
 Position Function
 Average Velocity
 Instantaneous Velocity
 Free Fall Problems
 Product Rule
 Quotient Rule
 Chain Rule
Lesson
 Implicit Differentiation
 Checkpoints
 A  page 146 #6
 B  page 146 #10
 C  page 146 #26
 D  page 146 #30
 E  page 147 #48
 F  page 147 #52
 G  page 147 #66
 H  page 148 #74
 I  page 148 #78
Exit Ticket
 Exit Ticket will be posted on the board in class.
 Lesson Objective(s) How can implicit differentiation be used to find the derivative?
Standard(s)  APC.5
APC.6 APC.7 APC.8 APC.9
Mathematical Practice(s)  #1  Make sense of problems and persevere in solving them
 #2  Reason abstractly and quantitatively
 #3  Construct viable arguments and critique the reasoning of others
 #4  Model with mathematics
